How to perform Magic Square Operation in a Matrix using Python3
By Priyam SurIn this Python tutorial, we are going to learn how to perform a magic square operation in a matrix in Python. Here we will show you an easy example so that you can understand this tutorial easily.
MAGIC SQUARE OPERATION IN PYTHON
A Magic Square is:
- The square is itself having smaller squares (same as a matrix) each containing a number.
- The numbers in each vertical, horizontal, and diagonal row add up to the same value.
- The dimension of the square matrix is an (odd integer x odd integer) e.g., 3×3, 5×5, 7×7.
An example of this is given below in the image, where the sum is 15 for every column or row.
magic square
To know about this interesting puzzle, Magic Square on Wikipedia
Now, let’s take a look at the code.
PROGRAM: Python program for magic square operation
#Function
def generateSquare(n):
# 2-D array with all
# slots set to 0
magicSquare = [[0 for x in range(n)]
for y in range(n)]
# initialize position of 1
i = n / 2
j = n - 1
# Fill the square by placing values
num = 1
while num <= (n * n):
if i == -1 and j == n: # 3rd condition
j = n - 2
i = 0
else:
# next number goes out of
# right side of square
if j == n:
j = 0
# next number goes
# out of upper side
if i < 0:
i = n - 1
if magicSquare[int(i)][int(j)]: # 2nd condition
j = j - 2
i = i + 1
continue
else:
magicSquare[int(i)][int(j)] = num
num = num + 1
j = j + 1
i = i - 1 # 1st condition
# Printing the square
print ("Magic Square for n =", n)
print ("Sum of each row or column",n * (n * n + 1) / 2, "\n")
for i in range(0, n):
for j in range(0, n):
print('%2d ' % (magicSquare[i][j]),end = '')
# To display output
# in matrix form
if j == n - 1:
print()
# Driver Code
# Works only when n is odd
n=int(input("Number of rows of the Magic Square:"))
generateSquare(n)OUTPUT 1:
Number of rows of the Magic Square:7 Magic Square for n = 7 Sum of each row or column 175.0 20 12 4 45 37 29 28 11 3 44 36 35 27 19 2 43 42 34 26 18 10 49 41 33 25 17 9 1 40 32 24 16 8 7 48 31 23 15 14 6 47 39 22 21 13 5 46 38 30
OUTPUT 2:
Number of rows of the Magic Square:5 Magic Square for n = 5 Sum of each row or column 65.0 9 3 22 16 15 2 21 20 14 8 25 19 13 7 1 18 12 6 5 24 11 10 4 23 17
Also Read:
Hey, nice idea, I have shared on my Twitter.
It looks like the code will produce the same numbers
every time though, which makes it a bit limited,
I was thinking of doing a GUI on the code and
making a puzzle game from it, but I’m not
experienced enough yet to modify it to make
up different solutions each time.
Nice job though.
it just work for odd numbers.if you input an even number,You will encounter an error on the 25th line
# Try this code…
A = [[0,0,0],[0,0,0],[0,0,0]]
count = 0
for c1 in range(1,10,1):
for c2 in range(1,10,1):
if c2==c1:
continue
for c3 in range(1,10,1):
if c3==c2 or c3==c1:
continue
for c4 in range(1,10,1):
if c4==c3 or c4==c2 or c4==c1:
continue
for c5 in range(1,10,1):
if c5==c4 or c5==c3 or c5==c2 or c5==c1:
continue
for c6 in range(1,10,1):
if c6==c5 or c6==c4 or c6==c3 or c6==c2 or c6==c1:
continue
for c7 in range(1,10,1):
if c7==c6 or c7==c5 or c7==c4 or c7==c3 or c7==c2 or c7==c1:
continue
for c8 in range(1,10,1):
if c8==c7 or c8==c6 or c8==c5 or c8==c4 or c8==c3 or c8==c2 or c8==c1:
continue
for c9 in range(1,10,1):
if c9==c8 or c9==c7 or c9==c6 or c9==c5 or c9==c4 or c9==c3 or c9==c2 or c9==c1:
continue
A[0][0]=c1
A[0][1]=c2
A[0][2]=c3
A[1][0]=c4
A[1][1]=c5
A[1][2]=c6
A[2][0]=c7
A[2][1]=c8
A[2][2]=c9
Check = True
if A[0][0]+A[0][1]+A[0][2]!=15:
Check=False #First Row
if A[1][0]+A[1][1]+A[1][2]!=15:
Check=False #Second Row
if A[2][0]+A[2][1]+A[2][2]!=15:
Check=False #Third Row
if A[0][0]+A[1][0]+A[2][0]!=15:
Check=False #First Column
if A[0][1]+A[1][1]+A[2][1]!=15:
Check=False #Second Column
if A[0][2]+A[1][2]+A[2][2]!=15:
Check=False #Third Column
if A[0][0]+A[1][1]+A[2][2]!=15:
Check=False #First Diagonal
if A[2][0]+A[1][1]+A[0][2]!=15:
Check=False #Second Diagonal
if Check:
count +=1
print(“Magic square number”, count)
for i in range(0,3,1):
for j in range(0,3,1):
print(A[i][j],end=” “)
print()
print()
I’m not sure if I’ve explained myself well; I have a set of either 25 or 28 numbers. These need to be placed in either a 5×5, 6×6, or 9×9 magic square. However, these 25 or 28 numbers cannot be replaced by other numbers. I want to place them in such a way that it forms a correct 5×5 or 9×9 or 6×6 magic square. Could you create a Python code or suggest the best solver for this? The program needs to place these 25 or 28 numbers into the correct slots so that both the main diagonals, as well as each row and column, conform to the rules of a regular magic square. It is more of a trial-and-error process, and the program may need to come up with additional numbers on its own to create a magic square as a solution(which is fine in case of magic square 9×9 of 6×6). I want it to generate the magic square based on the aforementioned conditions. i would be thankfull for it.
i hope you have python code for me which i can use or other scripts